土力學(xué)_盧廷浩__第二版_課后習(xí)題答案

1、土力學(xué)土力學(xué)11解：解：(1)A試樣100.083dmm?300.317dmm?600.928dmm?60100.92811.180.083udCd???22301060()0.3171.610.0830.928cdCdd????(1)B試樣100.0015dmm?300.003dmm?600.0066dmm?60100.00664.40.0015udCd???22301060()0.0030.910.00150.0066cdCdd??

2、??12解：已知：=15.3g=10.6g=2.70mSmSG飽和=1??rS又知：15.310.6=4.7gwSmmm???(1)含水量==0.443=44.3%wSmm??4.710.6(2)孔隙比0.4432.71.201.0SreGS?????(3)孔隙率1.20.54554.5%111.2ee???????(4)飽和密度及其重度32.71.21.77111.2SsatwGegcme?????????31.771017.7sat

3、satgkNm???????(5)浮密度及其重度31.771.00.77satwgcm????????30.77107.7gkNm???????(6)干密度及其重度32.71.01.23111.2SwdGgcme????????31.231012.3ddgkNm???????13解：解：?31.601.51110.06dgcm?????????2.701.01110.791.51sswddGe?????????????0.7929.3%

4、2.70satseG?????1.60100150.91110.06smVmg????????????(29.3%6%)150.935.2wsmmg????????14解：解：?1()(1)111swswswGGGnnen?????????(2)1111swwVwswswssVsswwrsrwsVVsmVVVmmVVVVGSeGSemVVVVVeee???????????????????????AA(3)11111swsswsswssw

5、swwswVsVsmmVmVVGGVVVVeeeV??????????????????????????18解：(1)對(duì)A土進(jìn)行分類①由粒徑分布曲線圖，查得粒徑大于0.075㎜的粗粒含量大于50%，所以A土屬于粗粒土；②粒徑大于2㎜的礫粒含量小于50%，所以A土屬于砂類，但小于0.075㎜的細(xì)粒含量為27%，在15%～50%之間，因而A土屬于細(xì)粒土質(zhì)砂；③由于A土的液限為16.0%，塑性指數(shù)，在17㎜塑性圖上落在ML區(qū)，故A土最后定名為粉

6、土質(zhì)砂(SM)。16133pI???(2)對(duì)B土進(jìn)行分類①由粒徑分布曲線圖，查得粒徑大于0.075㎜的粗粒含量大于50%，所以B土屬于粗粒土；②粒徑大于2㎜的礫粒含量小于50%，所以B土屬于砂類，但小于0.075㎜的細(xì)粒含量為28%，在15%～50%之間，因而B土屬于細(xì)粒土質(zhì)砂；③由于B土的液限為24.0%，塑性指數(shù)，在17㎜塑性圖上落在ML區(qū)，故B土最后定名為粉土質(zhì)砂(SC)。241410pI???(3)對(duì)C土進(jìn)行分類①由粒徑分布曲線

7、圖，查得粒徑大于0.075㎜的粗粒含量大于50%，所以C土屬于粗粒土；②粒徑大于2㎜的礫粒含量大于50%，所以C土屬于礫類土；③細(xì)粒含量為2%，少于5%，該土屬礫；④從圖中曲線查得，和分別為0.2㎜，0.45㎜和5.6㎜10d30d60d因此，土的不均勻系數(shù)60105.6280.2udCd???土的曲率系數(shù)22301060()0.450.180.25.6cdCdd????⑤由于，所以C土屬于級(jí)配不良礫(GP)。51~3ucCC??19解

8、：(1)?12ssmm?即1122ddVV???AA112211dVV??????22111(1)1.6520(112%)21.741.7dVV??????????萬(wàn)方(2)1.6530004950sdmVt?????t()4950(19%12%)346.5wsopmm?????????(3)2.721.01110.6481.65sswddGe????????????20.0%95%2.7279.8%0.648srGSe??????[2