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1、<p><b> 外文部分</b></p><p><b> Chapter2</b></p><p> Plane waves</p><p> 2.1 Introduction</p><p> In this chapter we present the foundati
2、ons of Fourier acoustics-plane wave expansions.This material is presented in depth to provide a firm foundation for the rest of the book ,introducing concepts like wavenumber space and the extrapolation of </p>&l
3、t;p> wavefields from one surface to another .Fouries acoustics is used to derive some famous tools for the radiation from planar sources; the Rayleigh integrals ,the Ewald sphere construction of farfield radiation, t
4、he first product theorem for arrays, vibrating plate radiation, and radiation classification theory. Finally,a new tool called supersonic intensity is introduced which is useful in locating acoustic sources on vibrating
5、structures.We begin the chapter with a review of some fundamentals; t</p><p> 2.2 The Wave Equation and Euler’s Equation</p><p> Let p(x,y,z,t) be an infinitesimal variation of acoustic pressu
6、re from its equilibrium value which satisfies the acoustic wave equation</p><p><b> (2.1)</b></p><p> for a homogeneous fluid with no viscosity .c is a constant and refers to the s
7、peed of sound in the medium .At c=343 m/s in air and c=1481 m/s in water. The right hand side of Eq.(2.1) indicates that there are no sources in the volume in which the equation is valid. In Cartesian coordinates</p&
8、gt;<p> A second equation which will be used throughout this book is called Euler’s equation,</p><p><b> (2.2)</b></p><p> Where (Greek letter upsilon) represents the veloc
9、ity vector with components ,,;</p><p><b> (2.3)</b></p><p> where i j and k are the unit vectors in the the x, y, and z directions, respectively, and the gradient in terms of the u
10、nit vectors as </p><p><b> (2.4)</b></p><p> We use the convention of a dot over a displacements quantity to indicate velocity as is done in Junger and Feit. The displacements in t
11、he three coordinate directions are given by u, v, and w .</p><p> The derivation of Eq.(2.2) is useful in developing some understanding of the physical meaning of p and . Let us proceed in this direction.&l
12、t;/p><p> Figure2.1 : Infinitesimal volume element to illustrate Euler’s equation</p><p> Figure 2.1 shows an infinitesimal volume element of fluidxyz, with the x axis as shown .All six faces exp
13、erience forces due to the pressure p in the fluid. It is important to realize that pressure is a scalar quantity. There is no direction associated with it .It has units of force per unit area , or Pascals.The following i
14、s the convention for pressure,</p><p> P﹥0 → Compression</p><p> P﹤0 → Rarefaction</p><p> At a specific point in a fluid .a positive pressure indicates that an infinitesimal vol
15、ume surrounding the point is under compression ,and forces are exerted outward from this volume. It follows that if the pressure at the left face of the cube in Fig. 2.1 is positive, then a force will be exerted in the p
16、ositive x direction of magnitude p(x,y,z)yz.</p><p> The pressure at the opposite face p(x+x,y,z)is exerted in the negative x direction. We expand p(x+x,y,z)in a Taylor series to first order, as shown in th
17、e figure .Note that the force arrows indicate the direction of force for positive pressure .Given the directions of force shown,the total force exerted on the volume in the x direction is </p><p> Now we in
18、voke Newton’s equation ,f =ma =m,where f is the force, and is the fluid density, yielding</p><p> Carrying out the same analysis in the y and z directions yields the following two equations:</p><
19、;p><b> and</b></p><p> We combine the above three equations into one using vectors yielding Eq(2.2) above, Euler’s Equation.</p><p> 2.3 Instantaneous Acoustic Intensity </
20、p><p> It is critical in the study of acoustics to understand certain energy relationships. Most important is the acoustic intensity vector. In the time domain it is called the instantaneous acoustic and is de
21、fined as </p><p> , (2.5)</p><p> with units of energy per unit time (power) per unit area, measured as (joules/s)/ or watts/. </p><p> The acoustic in
22、tensity is related to the energy density e through its divergence, </p><p> , (2.6)</p><p> where the divergence is </p><p><b> (2.7)</b>&
23、lt;/p><p> The energy density is given by</p><p><b> (2.8)</b></p><p> whereis the fluid compressibility,</p><p><b> (2.9)</b></p><p
24、> Equation (2.6) expresses the fact that an increase in the energy density at some point in the fluid is indicated by a negative divergence of the acoustic intensity vector; the intensity vectors are pointing into th
25、e region of increase in energy density. Figure 2.2 should make this clear.</p><p> If we reverse the arrows in Fig. 2.2, a positive divergence results and the energy density at the center must decrease, tha
26、t is,﹤0. This case represents an apparent source of energy at the center.</p><p> Figure2.2: Illustration of negative divergence of acoustic intensity.</p><p> The region at the center has an
27、increasing energy density with time ,that is, an apparent sink of energy.</p><p> 2.4 Steady State</p><p> To consider phenomena in the frequency domain ,we obtain the steady the steady state
28、solution through transforms </p><p><b> (2.10)</b></p><p> leading to the steady state solution </p><p><b> (2.11)</b></p><p> Equation (2.1
29、0) can be differentiated with respect to time to yield the important relationship</p><p><b> so that </b></p><p><b> (2.12)</b></p><p> where the calligra
30、phic letter f represents the Fourier transform of the time domain wave equation,Eq,(2.1), yielding the Helmholtz equation</p><p><b> (2.13)</b></p><p> where the acoustic wavenumbe
31、r is k=w/c,the frequency is given by ,</p><p> and is the function (x,y,z,).For simplicity of notation we drop the bar above the variable. It will be clear from the context of the discussion if the quantit
32、y is in the frequency or in the time domain. The Fourier transform of Euler’s equation, Eq .(2.2), becomes, in the frequency domain</p><p><b> (2.14) </b></p><p> where Eq.(2.12) h
33、as been used again for the time derivative.</p><p> 2.5 Time Averaged Acoustic Intensity</p><p> Now consider the intensity relationship for steady state fields .This is defined as the averag
34、e of the instantaneous intensity over a period T, where T=1/f and f is the excitation frequency:</p><p><b> (2.15)</b></p><p> Using complex variable notation this relationship be
35、comes</p><p><b> (2.16)</b></p><p> where stands for complex complex conjugate and Re for the real part .The one-half results from the time average process . is the average power o
36、ver one period passing through unit area. For example , the x component of this flow represents the power passing through an element of area .</p><p> Important in this chapter is the radiation from planar
37、 radiators .Of particular interest is the power flow crossing an infinite plane. For example, consider the total power crossing the corrdinate plane z=0, a quantity expressed is watts or joules persecond .We use the symb
38、ol to represent the total power in watts crossing the boundary:</p><p><b> (2.17)</b></p><p> If there are no sources in the upper half space, then is the total power radiated by
39、 has the same power passing through it, since is no absorption in the fluid and there are no sources above the boundary.</p><p> The equation of continuity,Eq.(2.6), becomes</p><p><b> (
40、2.18)</b></p><p> By the definition of stesdy state the energy density at time at time T is the same as the density at time 0, so that we have </p><p><b> (2.19)</b></p>
41、;<p> This means that in a source-free field the divergence of the time averaged acoustic intensity must always be zero. The only way the intensity field can have a non-zero divergence is if there are sources or
42、sinks of energy within the medium, or losses in the medium.</p><p> Plane Wave Expansion </p><p> We turn now to plane wave solutions of the wave equation in Cartesian coordinates .Th
43、ese solutions will be useful in the study of sources which are planar (or nearly planar) in geometry such as vibrating plates .We note that Eq.(2.1) is very similar to the equation for a vibrating string;</p><
44、p><b> (2.20)</b></p><p> whereis normal displacement of the string, and is the wave speed, a constant. A solution to this equation is given by </p><p><b> (2.21)</b&g
45、t;</p><p> where A and B are arbitrary constants. For this solution to satisfy Eq.(2.20) we must have</p><p><b> (2.22)</b></p><p> We introduce the string solution t
46、o understand the plane wave solutions of Eq.(2.1). In Eq .(2.21) is called the wavenumber in the x direction.</p><p> Consider the phase term in Eq. (2.21) given by . We track the crest of a wave traveling
47、down the string by choosing a constant value of phase and then following it as a function of position and time .The position of the crest .Choosing arbitrarily, is given by . Thus , is the velocity of the crest in the
48、positive x direction and is called the phase velocity of the wave. The solution corresponding to the second term in Eq. (2.21) is a wave traveling in the negative x direction. At a fixed time </p><p><b&g
49、t; (2.23)</b></p><p> is the wavelength in the x direction and is the distance over which the phase of the wave changes by when time is held constant.</p><p><b> 第二章</b><
50、;/p><p><b> 平面波</b></p><p><b> 2.1介紹</b></p><p> 在這章中我們提出傅立葉平面波擴展的基礎。這些觀點的提出以有利于像波速空間和推理這樣的書,引入概念提供一個堅固的基礎.從一個面到另一個面.傅立葉聲學的勵磁波被用來作為平面的來源.從輻射引出一些著名的理論; 整流場輻射的
51、微量部分,the Ewald半球建設,陣列的第一定理,振動盤輻射和輻射分類理論。 最后,在結構振動時定位聲音的來源時也是有用的,從而引出一個新的概念被稱為超音速強度。下面我們從一些基本概念引出平面波方程,Euler’s方程,和聲學的強度的概念。</p><p> 2.2平面波方程和Euler’s方程</p><p> 讓滿足平面波方程的其均衡值成為無窮小的變化聲波的壓力p ( x,y,
52、z,t )</p><p><b> (2.1)</b></p><p> 因為沒有粘性.c的一種同類的流體在水中和在空氣中的速度指的都是中等的.時在空氣中和在水中的聲速分別是c=343 m/s和c=1481 m/s。Eq.(2.1)的右邊方程表明在其中有效的區(qū)域中沒有來源。笛卡兒派認為</p><p> 將作為第二方程在整個書中被使用稱
53、為Euler’s方程,</p><p><b> (2.2)</b></p><p> 用組成部分,,代表速度矢量</p><p><b> (2.3)</b></p><p> i j和k在該處表示x,y,和z方向矢量, </p><p><b> (2
54、.4)</b></p><p> 我們使用關于置換的一個點的結論來作為表明速度數(shù)量在Junger和Feit中被完成。 三個置換協(xié)調方向用u,v,和w表示。</p><p> Eq.(2.2)的由來在對p的物理意義的理解時是有用的。 讓我們朝著這方向進行研究。</p><p> Figure2.1: 用無窮小的元素說明Euler’s方程</p&
55、gt;<p> 式(2.1)中用x,y,z表示無窮小的元素量,用x表示壓力p在流體中方向.六個面都受力。 總壓力是一等級的數(shù)量。 但沒有與它有關的方向.力在每個單元區(qū)域會隨著壓力變化,</p><p><b> P﹥0→壓縮</b></p><p><b> P﹤0→稀少</b></p><p> 流
56、體內,在壓力下a的一個具體的點的周圍的一無窮小的區(qū)域內是壓縮的,力在這點方向是向外。 如果在第2.1圖中的立方體的左面的壓力是向里的,那么一種力將朝著 p(x,y,z)yz.的x方向延伸。在相反面p(x+x,y,z)的壓力朝著負值x方向被延伸。 我們首先命令p(x+x,y,z)一個Taylor系列作為被引入量.力的箭頭方向表示力的正方向.,力在x的正方向延伸.</p><p> 我們現(xiàn)在調用Newton’s方程
57、, f =ma =m ,在其中f是力,是流體密度,得出</p><p> 在y和z方向實行同樣的分析得出如下兩個方程:</p><p><b> 和,</b></p><p> 我們把上述的三個方程結合到在上面的出Eq(2.2)就得出Euler’s方程。</p><p> 2.3瞬時聲學的強度</p>
58、<p> 它的研究重點在理解聲學中的一定的能量關系。重要的是大多數(shù)聲學的強度矢量.在時間領域中被使用并且被定義為瞬時聲學</p><p> , (2.5)</p><p> 能量在單元時間(力)和單元區(qū)域,單位為(焦耳/ 秒)/或者 watts/ .</p><p> 聲學強度其分歧與能量密度有關,<
59、/p><p> , (2.6)</p><p><b> 分歧所在的地方</b></p><p><b> (2.7)</b></p><p><b> 能量密度</b></p><p><b>
60、 (2.8)</b></p><p><b> 流動的可壓縮性,</b></p><p><b> (2.9)</b></p><p> 方程( 2.6 )表明在一些的能量密集的流體中強度矢量是減弱的.聲學強度矢量的分歧表明; 強度矢量在能量密度低的區(qū)域是增加的。 式(2.2)表達的很清楚。</p&
61、gt;<p> 如果我們在圖2.2中翻轉箭頭方向,中心的能量密度一定減少,分歧也可能減少,﹤0 這種情況表明中心明顯是一個能量來源。</p><p> 式2.2:表示聲學的強度的分歧。在該地區(qū)中心有一個增加的能量密度時間,,該時間內是能量是減弱的.</p><p><b> 2.4平衡狀態(tài) </b></p><p> 在頻
62、率領域,我們考慮通過解決轉變現(xiàn)象獲得穩(wěn)定的狀態(tài).</p><p><b> (2.10)</b></p><p><b> 穩(wěn)定的狀態(tài)</b></p><p><b> (2.11)</b></p><p> 方程( 2.10 )關于時間得出重要的關系</p>
63、;<p><b> 因此</b></p><p><b> (2.12)</b></p><p> Calligraphic理論中f代表傅立葉轉變,得出Helmholtz關于時間的平面波方程,Eq,(2.1 )</p><p><b> (2.13)</b></p>
64、<p> 的波的波速為k = w / c ,頻率為。 如果在頻率中或者在時間領域中,討論的結果是正確的。傅立葉轉變得出的Euler’s方程,Eq .(2.2 )在頻率領域中和Eq.(2.12)在時間領域中被生物研究充分利用.</p><p><b> (2.14)</b></p><p> 2.5平均時間的強度</p><p>
65、; 現(xiàn)在考慮強度關系在穩(wěn)定的狀態(tài)領域.在這時間區(qū)域被定義為強度的平均值,在其中T=1/f和f是激勵頻率:</p><p><b> (2.15)</b></p><p> 使用可變符號得出關系式為</p><p><b> (2.16)</b></p><p> 用可變符號表示的地方為真正
66、的部分.從時間開始和到一半時間的平均過程, 穿過單元區(qū)域的平均功率超過平均功率。 例如,x的組成部分的穿過該區(qū)域的一個元素的力的功率。</p><p> 在這章中重點是平面散熱器.特殊的地方該力是橫越一個無窮的平面的力量流。 例如,在z=0時瓦特和焦耳認為整個平面的被該力量橫越.我們認為全部能量通過該平面,用符號表示橫越邊界的力:</p><p><b> (2.17)<
67、;/b></p><p> 如果沒有上面的一半空間中的能量,那么被放射的整個的能量就會有穿過它的相同的能量,當流體在邊界上沒有能量的來源時。</p><p> 連續(xù)性的方程,Eq.(2.6 ),變成</p><p><b> (2.18)</b></p><p> stesdy理論在時間T內能量密度在零時間
68、與液體密度一樣,這樣我們有 (2.19)</p><p> 這意味著在一個自由領域中平均時間內聲波的強度必須總是零。 如果強度能量有非零的唯一的原因是能量源在媒介內減弱,能量在媒介的損失。</p><p><b> 2.6平面波擴展</b></p><p> 我們現(xiàn)在開始研究笛卡兒的平面波
69、方程.該結論將在研究諸如振動的幾何學中平面的來源時是有用的.類似于Eq.(2.1)振動的方程;</p><p><b> (2.20)</b></p><p> 在置換串的地方是而不是波度, 對于方程的一種解決辦法</p><p><b> (2.21)</b></p><p> 對于解決滿
70、足Eq.(2.20 )我們必須有</p><p><b> (2.22)</b></p><p> 我們解釋Eq.(2.1)時。 Eq.(2.21 )朝著x的方向被定義為波速。</p><p> 在Eq(2.21)中考慮階段時期. 我們把通過選擇階段的值作為峰值.在該位置一個波到達頂峰然后下降。 這樣,在x方向上到達的頂峰的速度被定義波的
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